个人简介
樽中酒不空
相关博文
- ·
- ·
- ·
- ·
- ·
- ·
- ·
- ·
- ·
- ·
分类： c/c
2016-11-03 17:39:47
(cryptography)
1 padding :
string text;
int len = text.size();
char cht = (aes_block_size - len�s_block_size);
for (int i = 0; i< (aes_block_size - len�s_block_size); i )
{
text.push_back(cht);
}
2 unpadding:
char cht = out[len-1];
for (int i = 0; i < cht; i )
{
if (out[len - i -1] != cht)
{
return len;
}
}
1 padding :
string text;
int len = text.size();
char cht = (aes_block_size - len�s_block_size);
for (int i = 0; i< (aes_block_size - len�s_block_size); i )
{
text.push_back(cht);
}
2 unpadding:
char cht = out[len-1];
for (int i = 0; i < cht; i )
{
if (out[len - i -1] != cht)
{
return len;
}
}
the padding will be one of:
01 02 02 03 03 03 04 04 04 04 05 05 05 05 05 etc.
this padding method (as well as the previous two) is well-defined if and only if n is less than 256.
example: in the following example the block size is 8 bytes and padding is required for 4 bytes
... | dd dd dd dd dd dd dd dd | dd dd dd dd 04 04 04 04 |
给主人留下些什么吧！~~